A baseball is thrown horizontally off a cliff with a speed of 7.3 ms-1. What is the vertical distance, to the nearest tenth of a meter, that the ball has fallen after 9.4 seconds?
To find the vertical distance the baseball has fallen after 9.4 seconds, we need to use the equation of motion for free fall:
y = uyt + 0.5gt^2
where:
y is the vertical distance (unknown)
uy is the initial vertical velocity (0 m/s, as the ball is thrown horizontally)
t is the time (9.4 s)
g is the acceleration due to gravity (9.8 m/s^2)
First, let's find the value of the vertical distance:
y = 0 + 0.5 * 9.8 * (9.4)^2
y = 0 + 0.5 * 9.8 * 88.36
y = 0 + 431.312
y ≈ 431.3 meters
Therefore, to the nearest tenth of a meter, the ball has fallen approximately 431.3 meters.