Blood takes about 1.50 s to pass through a 2.0-mm-long capillary. If the radius of the capillary is

5.00 u�m and the pressure drop is 2.60 kPa, calculate the viscosity of blood

not sure how to approach this. any help is appreciated!

Well, well, well, looks like we have a bloody question here! Don't worry, I'll help you approach it with a touch of humor.

To tackle this problem, we can use the Hagen-Poiseuille equation, which relates the flow rate of a fluid to its viscosity and the dimensions of the tube through which it flows. Introducing blood, the river of life, into this equation, let's calculate that viscosity!

The Hagen-Poiseuille equation is as follows:

Flow rate = (π * ΔP * r^4) / (8 * η * L)

Where:
- Flow rate is the amount of blood passing through the capillary per second (which we know is 1.00 s).
- ΔP is the pressure drop across the capillary (2.60 kPa).
- r is the radius of the capillary (5.00 μm = 5.00 × 10^-6 m).
- η is the viscosity of the blood (that's what we're trying to find out!).
- L is the length of the capillary (2.0 mm = 2.0 × 10^-3 m).

Now comes the fun part, let's plug in the numbers and crunch them!

1.00 = (π * 2.60 × 10^3 * (5.00 × 10^-6)^4) / (8 * η * 2.0 × 10^-3)

Ready? Let's solve for η!

η = (π * 2.60 × 10^3 * (5.00 × 10^-6)^4) / (8 * 1.00 * 2.0 × 10^-3)

η ≈ 2.84 × 10^-3 Pa·s

And voilà! The viscosity of blood is approximately 2.84 × 10^-3 Pa·s. Keep in mind that blood viscosity can vary depending on factors like temperature and hematocrit levels. But for now, we'll stick to this answer.

I hope I didn't make your blood boil with my silly jokes! If you have any more questions, feel free to ask.

To calculate the viscosity of blood, you can use Poiseuille's Law, which relates the flow rate of a fluid through a capillary to the pressure drop and the characteristics of the capillary.

Poiseuille's Law states that the volume flow rate (Q) of a Newtonian fluid through a cylindrical capillary is given by:

Q = (π * ΔP * r^4) / (8 * η * L)

Where:
- Q is the flow rate,
- ΔP is the pressure drop across the capillary,
- r is the radius of the capillary,
- η is the viscosity of the fluid, and
- L is the length of the capillary.

We know:
- ΔP = 2.60 kPa = 2.60 * 10^3 Pa
- r = 5.00 μm = 5.00 * 10^(-6) m
- L = 2.0 mm = 2.0 * 10^(-3) m

We need to find η (viscosity).

Rearranging Poiseuille's Law and solving for viscosity (η):

η = (π * ΔP * r^4 * L) / (8 * Q)

From the information given, we are given Q = L / t, where t is the time it takes for blood to pass through the capillary.

Plugging in the given values, let's calculate η:

η = (π * ΔP * r^4 * L) / (8 * Q)
η = (π * 2.60 * 10^3 Pa * (5.00 * 10^(-6) m)^4 * 2.0 * 10^(-3) m) / (8 * (2.0 * 10^(-3) m / 1.50 s))

Now, let's calculate η using a calculator:

η ≈ 1.73 * 10^(-3) Pa.s or kg/(m.s)

Therefore, the viscosity of blood is approximately 1.73 * 10^(-3) Pa.s or kg/(m.s).

To calculate the viscosity of blood, we can make use of Poiseuille's Law, which describes the flow of a Newtonian fluid through a cylindrical tube. The formula for Poiseuille's Law is:

Q = (π * ΔP * r^4) / (8ηL)

Where:
Q = flow rate of the fluid (blood)
ΔP = pressure drop across the capillary
r = radius of the capillary
η = viscosity of the fluid (blood)
L = length of the capillary

We are given the following information:
ΔP = 2.60 kPa = 2.60 * 10^3 Pa
r = 5.00 μm = 5.00 * 10^-6 m
L = 2.0 mm = 2.0 * 10^-3 m
Q = 1.50 s (time taken for blood to pass through)

We can rearrange the equation to solve for η:

η = (Q * 8ηL) / (π * ΔP * r^4)

To solve for η, we need to use an iterative approach, as η appears on both sides of the equation. We can start with an initial guess for η and then iteratively improve our estimate until we converge to a solution.

Here is a step-by-step approach to solve for η:

1. Guess an initial value for η (e.g., 0.0035 Pa·s).
2. Substitute the given values into the equation and calculate the right-hand side.
3. Divide the left-hand side by the right-hand side to get a new estimate for η.
4. Repeat steps 2-3 until the value of η converges (the difference between consecutive values becomes very small).
5. Once you have an accurate estimate for η, you can consider the problem solved.

Using this iterative approach, you can calculate an estimate for the viscosity of blood.