algebra

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factorise the left hand side of the equation xxx+7xx-21x-27=0 and the roots are

  • algebra -

    simplified to
    x^3 + 7x^2 - 21x - 27 = 0
    try: x = ±1, ±3, ±7
    on the second try, I got x=-1 to work
    so (x+1) is a factor
    by synthetic division I found
    x^3 + 7x^2 - 21x - 27 = (x+1)(x^2 + 6x - 27) = 0
    (x+1)(x+9)(x-3) = 0

    x = -1, -9, and 3

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