a man bought a certain number of toys for rs 180 and he broke two of them. Then he sold each of the rest for Rs.10 more than he had given for it and thereby he makes a profit for Rs 60. find the number of toys he initially bought

To solve this problem, we can set up some equations.

Let's assume that the man initially bought x number of toys.
Since each toy costs a certain amount, we can calculate the cost of one toy as 180/x rupees.

If the man broke two toys, he sold the remaining (x-2) toys.
He sold each of these toys for Rs. 10 more than he paid for it, so the selling price of each toy would be (180/x) + 10.

By selling (x-2) toys, the man earned a profit of Rs. 60.
The profit earned from selling (x-2) toys can be calculated as:
Profit = Selling Price - Cost Price
60 = [(180/x) + 10] - (180/x)

Now we can solve this equation to find the value of x.

To do this, we can multiply the entire equation by x to remove the denominators:
60x = (180 + 10x) - 180

Simplifying further:
60x = 10x
50x = 0

Dividing both sides by 50:
x = 0

However, a number of toys can't be zero, so there seems to be an error in the given information. Please recheck the problem statement and provide the correct values.