A sample of solid sulfur is heated with an electrical coil. If 105 joules of energy is added to a 12.4 gram sample initially at 24.4°C, what is the final temperature of the sulfur?
First you need to make sure that this is not in the range of the melting point for S. I checked and the m.p. is abou 115 C.
q = mass S x specific heat S x (Tfinal-Tintial).
You need the specific heat S. Substitute and solve for Tfinal.
To find the final temperature of the sulfur, we need to use the equation for heat transfer:
q = mcΔT
Where:
q = heat energy transferred (in joules)
m = mass of the sample (in grams)
c = specific heat capacity of sulfur (in J/g°C)
ΔT = change in temperature (in °C)
First, let's calculate the heat energy transferred (q):
q = 105 J
Next, we need to find the specific heat capacity of sulfur (c). The specific heat capacity of sulfur is approximately 0.22 J/g°C.
c = 0.22 J/g°C
Now, we can rearrange the equation to solve for ΔT:
ΔT = q / (mc)
Substituting the given values:
ΔT = 105 J / (12.4 g * 0.22 J/g°C)
Simplifying:
ΔT = 105 J / 2.728 g°C
ΔT ≈ 38.47 °C
Finally, to find the final temperature of the sulfur, we add the change in temperature (ΔT) to the initial temperature (24.4°C):
Final temperature = 24.4°C + 38.47°C
Final temperature ≈ 62.87 °C
Therefore, the final temperature of the sulfur is approximately 62.87 °C.
To find the final temperature of the sulfur, we can use the specific heat formula:
q = m * c * ΔT
Where:
q is the energy added to the sample (in joules),
m is the mass of the sample (in grams),
c is the specific heat capacity of the substance (in joules/gram°C), and
ΔT is the change in temperature (in °C).
First, we need to calculate the energy added to the sample. In this case, the energy is given as 105 joules.
Next, we need to determine the specific heat capacity of solid sulfur. The specific heat capacity of sulfur is typically around 0.71 joules/gram°C.
Now, we can rearrange the equation to solve for ΔT:
ΔT = q / (m * c)
Substituting the values we have:
ΔT = 105 J / (12.4 g * 0.71 J/g°C)
Simplifying:
ΔT ≈ 1.490°C
To find the final temperature, we add the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 24.4°C + 1.490°C
Final temperature ≈ 25.89°C
Therefore, the final temperature of the sulfur sample is approximately 25.89°C.