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solve for the value of x: 6log (x^2+1)-x=0. please help me because I do not have any idea in this topic.

6log(x^2+1)-x=0

6 log(x^2 + 1) = x
log(x^2 + 1) = x/6
x^2 + 1 = 10^(x/6)
wow ....

try Wolfram, since there is no "nice" way to solve this
http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+10%5E%28x%2F6%29+

It says: x = 0 or x = appr .416 or x = appr 13.63

check:
x = 0
LS = 6log 1 - 0 = 0 = RS , OK

x = .416
LS = 6log(1.173056) - .416 = -.00008 , not bad

x = 13.63
LS = 6log(186.7769) - 13.63 = -.00206 , not bad

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