You have a stock solution of 5.0 M H2SO4. How many mL of stock solution are required to make 136 mL of 1.6 M H2SO4 solution
Don't you know how to do any of these problems that you've posted in the last few minutes?
Not when I do not have a book that is cooperating with me. I have an online course and my book keeps freezing so I am unable to look anything up to make sure I am doing these equations and formulas right.
You are diluting it 5/1.5 times=10/3=3 1/3 times
That means 1 part stock, 2 1/3 parts water
what is one part? 136ml*10/3
what is two parts? 136*20/3
To determine how many mL of the stock solution are required to make the desired solution, we can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the stock solution
V1 = volume of the stock solution to be used
C2 = concentration of the desired solution
V2 = final volume of the desired solution
Let's plug in the given values:
C1 = 5.0 M
C2 = 1.6 M
V2 = 136 mL
Now, we can rearrange the formula to solve for V1:
V1 = (C2 * V2) / C1
V1 = (1.6 M * 136 mL) / 5.0 M
V1 ≈ 43.52 mL
Therefore, approximately 43.52 mL of the stock solution are required to make 136 mL of 1.6 M H2SO4 solution.