Calculus
posted by Molly .
what is the second derivative of (x^36x)^11 that is fully simplex

Calculus 
Steve
y=(x^36x)^11
y' = 33(x^22)(x^36x)^10
y" = 132(8x^433x^2+30)(x^36x)^9
not sure what you mean by fully simplex for a derivative.
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