Thimerosal is an organic compound (gram molecular mass = 404.8 g/mol) used to inhibit bacterial growth. A .100%solution of thimerosal is sometimes used as an antiseptic. Assume that this solution has a density of 1.00 g/mL.
A. how many grams of thimerosal are found in .500 g of .100% solution?
B. how many grams of thimerosal must be mixed with 25.0 g of water to make a .100% solution?
C. what mass of thimerosal must be mixed with 25.0 g of wwater to make a 0.100% solution?
D. how many grams of thimerosal are required to make 75.0 mL of .100% solution?
E. what volume of .100% solution contains 0.750 g of thimerosal?
A. I don't know the exact answer, but the good news is that thimerosal won't make you a better comedian.
B. You know, mixing thimerosal with water is like mixing clown makeup with water - it might not end up looking too good.
C. Well, if you mix thimerosal with water, make sure to mix it gently, otherwise you might end up with a thimerosal whirlpool.
D. If you have 75.0 mL of thimerosal, you might want to consider starting your own circus instead of making a solution.
E. You know, trying to measure the volume of a solution that contains thimerosal is like trying to measure the height of a clown's wig - it's just not worth the effort.
To solve these problems, we need to use the given information and apply the relevant formulas.
A. To find the grams of thimerosal in 0.500 g of a 0.100% solution, we need to find the mass fraction of thimerosal in the solution and multiply it by the total mass of the solution.
Mass fraction of thimerosal = 0.100%
Total mass of the solution = 0.500 g
Grams of thimerosal = Mass fraction * Total mass
Grams of thimerosal = 0.100% * 0.500 g
Grams of thimerosal = (0.100/100) * 0.500 g
Grams of thimerosal = 0.001 * 0.500 g
Grams of thimerosal = 0.0005 g
Therefore, there are 0.0005 grams of thimerosal in 0.500 g of the 0.100% solution.
B. To find the grams of thimerosal that need to be mixed with 25.0 g of water to make a 0.100% solution, we need to determine the total mass of the solution and the mass fraction of thimerosal.
Total mass of the solution = mass of thimerosal + mass of water
Total mass of the solution = x + 25.0 g (where x is the mass of thimerosal in grams)
Mass fraction of thimerosal = 0.100%
Mass fraction = mass of thimerosal / total mass of the solution
0.100% = x / (x + 25.0 g)
To solve for x, we can cross-multiply and solve the resulting equation:
0.100% * (x + 25.0 g) = x
(0.100/100) * (x + 25.0 g) = x
0.001 * (x + 25.0 g) = x
0.001x + 0.025 g = x
0.025 g = 0.999x
x = 0.025 g / 0.999
x ≈ 0.025 g
Therefore, approximately 0.025 grams of thimerosal must be mixed with 25.0 g of water to make a 0.100% solution.
C. To find the mass of thimerosal that must be mixed with 25.0 g of water to make a 0.100% solution, we can simply use the value of x from the previous calculation:
Mass of thimerosal = 0.025 g
Therefore, 0.025 grams of thimerosal must be mixed with 25.0 g of water to make a 0.100% solution.
D. To find the grams of thimerosal required to make 75.0 mL of a 0.100% solution, we need to know the density of the solution:
Density = 1.00 g/mL
Volume = 75.0 mL
Mass = Density * Volume
Mass = 1.00 g/mL * 75.0 mL
Mass = 75.0 g
Therefore, 75.0 grams of thimerosal are required to make 75.0 mL of a 0.100% solution.
E. To find the volume of a 0.100% solution that contains 0.750 g of thimerosal, we can use the density of the solution:
Density = 1.00 g/mL
Mass = 0.750 g
Volume = Mass / Density
Volume = 0.750 g / 1.00 g/mL
Volume = 0.750 mL
Therefore, 0.750 mL of a 0.100% solution contains 0.750 g of thimerosal.
To solve these questions, we need to use the concept of percent concentration and the density of the solution.
The percent concentration is defined as the amount of solute (in this case, thimerosal) divided by the total amount of solution (solution + solute), multiplied by 100.
A. To find the grams of thimerosal in 0.500 g of a 0.100% solution, we can use the percent concentration formula:
% concentration = (mass of solute / mass of solution) * 100
Let "x" be the mass of thimerosal in grams. We can set up the following equation:
0.100% = (x / 0.500 g) * 100
To isolate "x," we can rearrange the equation:
x = (0.100% / 100) * 0.500 g = 0.001 g
Therefore, there are 0.001 grams of thimerosal in 0.500 g of a 0.100% solution.
B. To find the grams of thimerosal required to make a 0.100% solution with 25.0 g of water, we need to determine the mass of the solution. We can set up the following equation:
% concentration = (mass of solute / mass of solution) * 100
Let "y" be the mass of the solution. We can set up the following equation:
0.100% = (x / (y + 25.0 g)) * 100
We know that the mass of water is 25.0 g, so we can substitute this value:
0.100% = (x / (y + 25.0 g)) * 100
To isolate "x," we can rearrange the equation:
x = (0.100% / 100) * (y + 25.0 g)
We can simplify this equation as:
x = 0.001* (y + 25.0 g)
Therefore, the grams of thimerosal required is 0.001 times the sum of the mass of the solution and 25.0 g of water.
C. The question asks for the mass of thimerosal that needs to be mixed with 25.0 g of water to make a 0.100% solution. We already determined that the grams of thimerosal required is 0.001 times the sum of the mass of the solution and 25.0 g of water. So, the mass of thimerosal required is the same as the value we found in the previous question, which is 0.001 g.
D. To find the grams of thimerosal required to make 75.0 mL of a 0.100% solution, we need to consider the density of the solution. Since the density is given as 1.00 g/mL, the mass of the solution is equal to its volume in mL. Therefore, the mass of the solution is 75.0 g.
Using the percent concentration formula, we can set up the following equation:
0.100% = (x / 75.0 g) * 100
To isolate "x," we can rearrange the equation:
x = (0.100% / 100) * 75.0 g = 0.075 g
Therefore, 0.075 grams of thimerosal are required to make 75.0 mL of a 0.100% solution.
E. To find the volume of a 0.100% solution that contains 0.750 g of thimerosal, we can use the density of the solution to convert the mass to volume.
Since the density is given as 1.00 g/mL, the volume is equal to the mass.
Therefore, the volume of the 0.100% solution that contains 0.750 g of thimerosal is 0.750 mL.