Precalculus
posted by marie darling .
Solve sin(x) = 0.36 on 0 le x lt 2pi
There are two solutions, A and B, with A < B and A and B in radians to 4 decimal places.

le= (less than or equal to)
lt= (less than) 
Here is how I do these.
First I decide in which quadrant the angles are.
Since sinx is negative, x must be in quads III or IV.
I then find the angle in standard position by finding sin^1 (+.36) which is
.36826.. (in radians) or 21.1 degrees
so x = pi + .36826 or x = 2pi  .36826
in degrees x = 201.1 or 338.9 
Thank you for your help!
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