# Precalculus

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Solve sin(x) = -0.36 on 0 le x lt 2pi

There are two solutions, A and B, with A < B and A and B in radians to 4 decimal places.

• Precalculus -

le= (less than or equal to)
lt= (less than)

• Precalculus -

Here is how I do these.
First I decide in which quadrant the angles are.
Since sinx is negative, x must be in quads III or IV.
I then find the angle in standard position by finding sin^-1 (+.36) which is
.36826.. (in radians) or 21.1 degrees
so x = pi + .36826 or x = 2pi - .36826

in degrees x = 201.1 or 338.9

• Precalculus -

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