algebra
posted by Taylor .
A rectangular picture is 2 inches longer than it is wide. When a frame 3 inches wide is placed around the picture, the area covered by the picture and frame is 168 square inches greater than the area covered by the picture alone. What are the dimensions of the picture?

Let x = original width, then x+2 = length
(x+3)(x+5)  x(x+2) = 168
Solove for x.