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A solution is made by dissolving 0.10 mole of Na2SO4 in water to a final volume of 1.00 L. What is the molar concentration of Na+ ions in the solution?

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    Conc=n/v
    c=0.1mol/1L
    C=0.1mol/l
    concentration with respect to ion=stoichiometric value*conc of solution
    Na2SO4--->2Na^+1 + SO4^-2
    hence conc of Na^+1=2*0.1mol/l
    =0.2mol/litre

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