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Algebra II

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write a fourth degree polynomial function a leading coefficient o 1 given three of its zeros are -1, 3 and 2i, then re-write it in simplified form.

  • Algebra II -

    The key concept here is that imaginary numbers always appear as conjugates
    so if 2i is a zero, so is -2a
    so we would have x = ±2i
    x^2 = 4i^2
    x^2 = -4
    so x^2 + 4 is a factor

    the polynomial is
    f(x) = (x+1)(x-3)(x^2 + 4)

    I will leave it up to you to expand it, but I would consider the factored form more simplified than the expanded form.

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