Questions LLC
Login
or
Sign Up
Ask a New Question
Algebra
Trigonometry
Trigonometric Identities
Sin^2 b(1 +cot^2 b) =1
1 answer
csc^2 = 1+cot^2, so you have
sin^2 b csc^2 b = 1
You can
ask a new question
or
answer this question
.
Similar Questions
A right triangle has acute angles C and D. If tan C=158 and cos D=1517, what are cot D and sin C?
cot D=8/15 and sin C=8/17 cot
Top answer:
I labelled the triangle CDE, with E as the right angle. All you have to do is recognize that your
Read more.
Simplify the trigonometric function
sin^4x-cos^4x cos^2â-sin^2â=1+2cosâ (1+cot^2x )(cos^2x )=cot^2x
Top answer:
sin^4x-cos^4x = (sin^2 x+cos^2 x)(sin^2 x -cos^2 x = 1 (sin^2 x - cos^2 x) = 2 sin^2 x - 1
Read more.
use the quotient and reciprocal identities to simplify the given expression
cot t sin t csc t sin t tan t cot t cot t sec t
Top answer:
cot t sin t csc t sin t tan t cot t cot t sec t
Read more.
For all values x for which the terms are defined, fidnteh value(s) of k, 0<k<1, such that
cot(x/4) - cot(x) =
Top answer:
That is a very confusing question, you may want to reword that if you want an answer
Read more.
Verify the identity.
(csc(2x) - sin(2x))/cot(2x)=cos(2x) =csc(2x)/cot(2x) - sin(2x)/cot(2x) =csc(2x)/cot(2x) - cos(2x) Is this
Top answer:
Oops. sin/cot = sin*tan = sin^2/cos csc/cot = 1/sin * sin/cos = 1/cos You should have said
Read more.
sorry, another I can't figure out
Show that (1-cot^2x)/(tan^2x-1)=cot^2x I started by factoring both as difference of squares.
Top answer:
I don't think your equation is an identity, I tried several angles and the Left Side is not equal to
Read more.
I posted this question before at 7:14
I think the answer to it is 0. cot(40) - ((sin(50))/(sin(40)) = ? these are also degrees
Top answer:
sin50=cos40 then ctn(40)-cos/sin= ctn(40)-ctn(40)=zilch
Read more.
Find the values of the trigonometric function cot -8/17
sin: sec: tan: cot: I know you use a Pythagorean Identity, sin^2t +
Top answer:
Your terminology is awful cot - 8/17 is meaningless I will assume you were given cot Ø = -8/17 and
Read more.
How do I do these problems?
Verify the identity. a= alpha, b=beta, t= theta 1. (1 + sin a) (1 - sin a)= cos^2a 2. cos^2b - sin^2b
Top answer:
Learn your identites well in order to prove these. 1. (1+sina) (1-sina) = 1-sina+sina-sin^2a =
Read more.
Verify the identities.
1.) √1-COSθ/1+COSθ= 1+SINθ/SINθ 2.) SEC X SIN(π/2-X)= 1 3.) CSC X(CSC X-SIN X)+SIN X-COS X/SIN X +
Top answer:
2.) SEC X COS X= 1 1/COS X*COS X/1= 1 BINGO! 3.) CSC²X-CSC X SIN X+SIN X/SINX-TAN X+ COS X/SIN X
Read more.
Related Questions
Which of the following are trigonometric identities? Select all that apply (there are 3 answers).
A cos^2(theta)=sin^2(theta)-1 B
Someone please help!!!?
7. What is 1/cot(x) in terms of sine? This is what I've got so far: sin = 1/csc tan = 1/cot 1+cot2(x) =
Justin wants to evaluate 3cot(-5pi/4). Which of the following identities can he use to help him? Select two answers.
cot(-theta)
Since cot x = cos x / sin x, if cot x = 1/2, with the angle x in the first quadrant,
then cos x = 1 and sin x = 2 (1) State true
State the restrictions on the variables for these trigonometric identities.
a)(1 + 2 sin x cos x)/ (sin x + cos x) = sin x + cos
If A+B+C=180 and sin a= sin b sin c prove that
cot a= 1- cot b cot c
Prove that each equation is an identity.
I tried to do the problems, but I am stuck. 1. cos^4 t-sin^4 t=1-2sin^2 t 2. 1/cos s=
Verify the identities.
1.) SIN[(π/2)-X]/COS[(π/2)-X]=COT X 2.) SEC(-X)/CSC(-X)= -TAN X 3.) (1 + SIN Y)[1 + SIN(-Y)]= COS²Y 4.)
Find the complete solution of each equation. Express your answer in degrees.
sec^2 θ+sec θ=0 2 cos^2 θ+1=0 cot θ=cot^2 θ
Find the complete solution of each equation. Express your answer in degrees.
sec^2 θ+sec θ=0 2 cos^2 θ+1=0 cot θ=cot^2 θ