Alg 1
posted by Jane .
Operations with radical expressions:
Simplify each quotient
7/sq rt 2  sq rt 3
Please solve and explain how you did it. What do you do when the denominator is a negative?

7/(√2√3)
since (ab)(a+b) = a^2b^2,
= 7/(√2√3) * (√2+√3)/(√2+√3)
= 7(√2+√3)/(23)
= 7(√2+√3)
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