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Please help me because I do not any idea in Logarithm topic.Solve for the value of X: 6log(x^2+1)=5

6log(x^2 + 1) = 5
log(x^2 + 1 = 5/6
x^2+ 1 = 10^(5/6) , by definition of logs
x^2 = 10^5/6) - 1
x = ±√(10^(5/6 - 1)
= appr ± 2.41

check:
6 log(2.41^1 + 1)
= 6log 6.8081
= 6(.83302...) = 4.9981.. , not bad

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