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Physics

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A jogger starting morning run accelerates from a stand still to their jogging pace of 8km/hr. They reach a speed of 8km/hr 5 seconds after starting. How long does it take the jogger to reach the end of their 20m driveway?

  • Physics -

    V = 8km/h = 8000m/3600s = 2.22m/s.

    0.5a = (V-Vo)/t = (2.22-0)/5 = 0.444 m/s^2

    d = 0.5a*t^2 = 20 m.
    0.222*t^2 = 20
    t^2 = 90.1
    t = 9.49 s.

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