posted by Parshu Ram .
A jogger starting morning run accelerates from a stand still to their jogging pace of 8km/hr. They reach a speed of 8km/hr 5 seconds after starting. How long does it take the jogger to reach the end of their 20m driveway?
V = 8km/h = 8000m/3600s = 2.22m/s.
0.5a = (V-Vo)/t = (2.22-0)/5 = 0.444 m/s^2
d = 0.5a*t^2 = 20 m.
0.222*t^2 = 20
t^2 = 90.1
t = 9.49 s.