determine how many grams of N2 are produced by 9.12 g of H2O2 and 6.90 g of N2H4. 2H2O2+N2H4= 4H2O+N2
This is a limiting reagent problem. I know that because amounts are given for BOTH reactants.
mols H2O2 = grams/molar mass
mols N2H4 = grams/molar mass
Convert mols H2O2 to mols N2.
Convert mols N2H4 to mols N2.
It is likely the two values for mols N2 will not agree which means one of them is not right. The correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Then, using the smaller value, convert to grams. mols x molar mass = grams.
To determine how many grams of N2 are produced by 9.12 g of H2O2 (hydrogen peroxide) and 6.90 g of N2H4 (hydrazine), we need to use stoichiometry and balanced equation.
The balanced equation given is:
2 H2O2 + N2H4 → 4 H2O + N2
First, we need to find the limiting reactant, which is the reactant that will be completely consumed and will limit the amount of product formed. To do this, we need to compare the given masses of H2O2 and N2H4 to their respective molar masses.
The molar mass of H2O2 is:
2(1.01 g/mol for hydrogen) + 2(16.00 g/mol for oxygen) = 34.02 g/mol
The molar mass of N2H4 is:
2(1.01 g/mol for hydrogen) + 4(14.01 g/mol for nitrogen) = 32.05 g/mol
Next, we need to calculate the number of moles for each reactant by dividing the given masses by their respective molar masses.
Number of moles of H2O2 = 9.12 g / 34.02 g/mol
Number of moles of N2H4 = 6.90 g / 32.05 g/mol
Now, let's determine which reactant is the limiting reactant. To do this, we compare the mole ratios between the reactants and the product N2.
From the balanced equation, the mole ratio between N2H4 and N2 is 1:1. This means that for each mole of N2H4, we get 1 mole of N2.
From the balanced equation, the mole ratio between H2O2 and N2 is 2:1. This means that for every 2 moles of H2O2, we get 1 mole of N2.
Now, we can calculate the number of moles of N2 produced from each reactant.
Moles of N2 produced from H2O2 = (Number of moles of H2O2) / 2
Moles of N2 produced from N2H4 = Number of moles of N2H4
Finally, we compare the moles of N2 produced from each reactant. The smaller value represents the amount of N2 that can be produced.
Now, we can calculate the number of grams of N2 produced.
Grams of N2 = Moles of N2 produced x Molar mass of N2
Keep in mind that the given balanced equation assumes all reactants are fully consumed, and the reaction goes to completion.