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Pythagorean Theorem

A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.

  • Math -

    Try to put it through the circle using the smaller end
    that is, the 9 by 11 end
    We need the diameter of that rectangle

    x^2 = 9^2 + 11^2 = 202
    x = √202 = appr 14.2

    so the circle will have to be > 14.2

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