y1=6+2x
x1 y1
-3 ?
-2 ?
-1 ?
To find the values of y given different values of x using the equation y1 = 6 + 2x, you can simply substitute each value of x into the equation and solve for y1.
Let's apply this process to find the values of y1 for the given x1 values:
For x1 = -3:
Substituting x1 = -3 into the equation y1 = 6 + 2x, we get:
y1 = 6 + 2(-3)
y1 = 6 - 6
y1 = 0
So, when x1 = -3, y1 is equal to 0.
For x1 = -2:
Substituting x1 = -2 into the equation y1 = 6 + 2x, we get:
y1 = 6 + 2(-2)
y1 = 6 - 4
y1 = 2
So, when x1 = -2, y1 is equal to 2.
For x1 = -1:
Substituting x1 = -1 into the equation y1 = 6 + 2x, we get:
y1 = 6 + 2(-1)
y1 = 6 - 2
y1 = 4
So, when x1 = -1, y1 is equal to 4.
Therefore, the values of y1 for the given x1 values are:
y1 = 0 when x1 = -3
y1 = 2 when x1 = -2
y1 = 4 when x1 = -1