Can someone please check to see if I am doing this correctly. Thank you :)

Q) Calculate the new molarity of a 35mL sample of 0.450 M CaCl2 solution that is diluted with enough water to make 250 mL of solution.

A) 0.450 m CaCl2 x 35mL/250mL = 0.063 mL diluted solution

To calculate the new molarity of a solution after dilution, you can use the formula:

M1V1 = M2V2

Where:
M1 = Initial molarity of the solution
V1 = Initial volume of the solution
M2 = Final molarity of the solution (what we are trying to find)
V2 = Final volume of the solution

In this case, the initial molarity (M1) is given as 0.450 M, and the initial volume (V1) is 35 mL. The final volume (V2) is given as 250 mL, and we need to find the final molarity (M2).

Plugging the values into the formula:

0.450 M x 35 mL = M2 x 250 mL

Now, let's solve for M2:

(0.450 M x 35 mL) / 250 mL = M2

0.063 M = M2

Therefore, the new molarity of the diluted solution is 0.063 M (or 0.063 mol/L).

To recap:

- Calculate the new molarity of a solution after dilution, use the formula M1V1 = M2V2.
- Plug the given values into the formula.
- Solve for the unknown variable (M2).
- In this case, the new molarity is found to be 0.063 M.