how many calories of heat energy are required to warm 250ml of water from 35 degrees celsius to 64 degrees celsius?
To calculate the calories of heat energy required to warm water, we can use the equation:
Q = m * c * ΔT
Where:
Q represents the calories of heat energy,
m represents the mass of water in grams,
c represents the specific heat capacity of water in calories/gram°C, and
ΔT represents the change in temperature in °C.
In your case, you have 250 ml of water and want to warm it from 35°C to 64°C. To use the equation, we need to convert the volume (ml) to mass (grams) by multiplying it by the density of water, which is approximately 1 gram/ml.
Mass (m) = 250 ml * 1 g/ml = 250 g
The specific heat capacity (c) of water is about 1 calorie/gram°C.
Now, we can calculate the change in temperature (ΔT):
ΔT = Final temperature - Initial temperature = 64°C - 35°C = 29°C
Finally, we can use the formula to determine the calories of heat energy (Q):
Q = 250 g * 1 calorie/gram°C * 29°C
Q = 7250 calories
Therefore, approximately 7250 calories of heat energy are required to warm 250 ml of water from 35°C to 64°C.