Evaluate 2y^2(x+y) when x=1 and y=7

=2(1)^2(1+7)

=16

These are my choices ...

A . 203 B. 784 C. 105 D. 392

sorry my mistake

its
=2(7)^2(1+7)
=784
that is c

To evaluate the expression 2y^2(x+y) when x = 1 and y = 7, follow these steps:

Step 1: Replace the x variable with the given value, x = 1.
2y^2(1+y)

Step 2: Replace the y variable with the given value, y = 7.
2(7)^2(1+7)

Step 3: Simplify the expression.
2(49)(8)
98(8)
784

Therefore, when x = 1 and y = 7, the expression 2y^2(x+y) evaluates to 784.