Evaluate 2y^2(x+y) when x=1 and y=7
=2(1)^2(1+7)
=16
These are my choices ...
A . 203 B. 784 C. 105 D. 392
sorry my mistake
its
=2(7)^2(1+7)
=784
that is c
To evaluate the expression 2y^2(x+y) when x = 1 and y = 7, follow these steps:
Step 1: Replace the x variable with the given value, x = 1.
2y^2(1+y)
Step 2: Replace the y variable with the given value, y = 7.
2(7)^2(1+7)
Step 3: Simplify the expression.
2(49)(8)
98(8)
784
Therefore, when x = 1 and y = 7, the expression 2y^2(x+y) evaluates to 784.