Algebra
posted by Elizabeth .
A baseball player hits a baseball into the air with an initial vertical velocity of 48 feet per second from a
height of 3 feet.
8. Write an equation that gives the baseball’s height as a function of the time (in seconds) after it is hit.
9. After how many seconds does the baseball reach its maximum height?
10. What is the maximum height?

height = 16t^2 + 48t + 3
using Calculus,
d(height)/dt = velocity = 32t + 48
= 0 at a max of height
32t = 48
t = 48/32 = 1.5
Maximum height is reached after 1.5 seconds
that height is
16(1.5)^2 + 48(1.5) + 3 = 39 ft
If you don't know Calculus, then you have to find the vertex of the above parabola, usually by completing the square.
A shortcut would be to find the x of the vertex by
b/(2a) = 48/(32) = 1.5
then subbing in just like before to the actual maximum
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