A circle has a radius that increases at a rate of 10cm/s. Find the eaaquation of the outermost circle 6 seconds after it starts to expand.

Equation for what, the circumference?

C=2PI r
dC/dt=2PI dr/dt

For area:
Area=PI r^2
dA/dt=2PI r dr/dt

but r=10+6t
dA/dt=2pi(10+36)10

Thank u

To find the equation of the outermost circle after it starts to expand, we need to consider the formula for the equation of a circle.

The equation of a circle with the center (h, k) and radius r is given by:
(x - h)^2 + (y - k)^2 = r^2

In this case, the center of the circle is not given explicitly, but we can assume that it starts at the origin (0,0) since no other information is provided.

Given that the radius is increasing at a rate of 10 cm/s, after 6 seconds, the radius would have increased by 10 cm/s * 6 s = 60 cm.

Thus, after 6 seconds, the outermost circle would have a radius of 60 cm.

Substituting the values into the equation of a circle, we get:
(x - 0)^2 + (y - 0)^2 = 60^2

Simplifying, we get:
x^2 + y^2 = 3600

So, the equation of the outermost circle 6 seconds after it starts to expand is x^2 + y^2 = 3600.