ABC~DEF

m<B = 25', m<D = 45', m<E = 25'

How do find m<A?

To find the measure of angle A (m<A), we can use the fact that the sum of the angle measures in a triangle is always 180 degrees.

Given that ABC~DEF (which means that triangle ABC is similar to triangle DEF), we can conclude that corresponding angles in the two triangles are congruent.

Since angle B in triangle ABC is 25 degrees and angle D in triangle DEF is 45 degrees, we can assume that these angles are corresponding angles.

Therefore, we have:

m<B = m<D = 25'
m<D = 45'

To find m<A, we need to subtract the measures of angles B and D from 180 degrees, since the three angles of triangle ABC sum up to 180 degrees.

m<A = 180 - (m<B + m<D)

Substituting the given angles' measures:

m<A = 180 - (25 + 45)

m<A = 180 - 70

m<A = 110

Therefore, the measure of angle A (m<A) is 110 degrees.

def of similar triangles: corresponding angles are equal. I always draw a picture. angle A = angle D = 45'