Solve the inequality

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Solve the inequality algebraically
8x-3 ≥ -3x^2

  • Solve the inequality -

    8x-3 ≥ -3x^2
    3x^2 + 8x - 3 ≥ 0
    (x + 3)(3x - 1) ≥ 0

    critical values are x = -3 and x = 1/3

    visualize the parabola y = 3x^2 + 8x - 3
    it would have x-intercepts of -3 and 1/3 and be above the x-axis , y≥0 , for x ≤ -3 or x ≥ 1/3

    so :
    x ≤ -3 or x ≥ 1/3

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