write and balance Solid aluminum carbonate decomposes to form solid aluminum oxide and carbon dioxide and carbon dioxide gas

I assume you made a typo with CO2 twice.

Al2(CO3)(s) ==> Al2O3(s) + 3CO2(g)

Well, well, well... looks like we have some chemistry going on here! Let's give it a shot, shall we?

The balanced equation for the decomposition of solid aluminum carbonate to form solid aluminum oxide and carbon dioxide gas would be:

2Al2(CO3)3 → 4Al2O3 + 6CO2

Ah, just picture it: solid aluminum carbonate breaking apart into solid aluminum oxide and carbon dioxide, which fills the air with its fizzy presence! Quite the spectacle, I must say. Just remember, always keep your chemical equations balanced like a tightrope walker... or in this case, a clown on a unicycle!

To write and balance the chemical equation for the decomposition of solid aluminum carbonate, we need to consider the conservation of mass and atoms. The general formula for aluminum carbonate is Al2(CO3)3.

Step 1: Write the equation:
Al2(CO3)3 → Al2O3 + CO2

Step 2: Count the number of atoms on both sides of the equation.
On the reactant side (left side):
Al: 2
C: 3
O: 9

On the product side (right side):
Al: 2
C: 1
O: 3

Step 3: Balance the equation by adjusting the coefficients. Start with the most complex molecule, aluminum carbonate (Al2(CO3)3).

Al2(CO3)3 → Al2O3 + 3 CO2

Now let's count the atoms again to check the balance:

On the reactant side (left side):
Al: 2
C: 3
O: 9

On the product side (right side):
Al: 2
C: (3 × 1) = 3
O: (2 × 3) = 6

The equation is now balanced with equal numbers of atoms on both sides. The balanced equation for the decomposition of solid aluminum carbonate is:

2 Al2(CO3)3 → Al2O3 + 3 CO2

To balance the chemical equation for the decomposition of solid aluminum carbonate (Al2(CO3)3) into solid aluminum oxide (Al2O3) and carbon dioxide (CO2) gas, you need to make sure that there is an equal number of atoms on both sides of the equation.

Here's how to balance the equation step-by-step:

1. Start by counting the number of atoms for each element on both sides of the equation.

Aluminum (Al): 2 on the left, 2 on the right
Carbon (C): 3 on the left, 1 on the right
Oxygen (O): 9 on the left, 3 on the right

2. The easiest way to balance this equation is by adjusting the coefficients (numbers in front of the chemical formulas). Let's start by balancing the carbon atoms.

To equalize the number of carbon atoms, we need to ensure that there are 3 carbon atoms on the right side of the equation. We can achieve this by placing a coefficient of 3 in front of the CO2:

Al2(CO3)3 -> Al2O3 + 3CO2

3. Now, let's balance the oxygen atoms.

On the left side, there are 3 oxygen atoms in each carbonate ion (CO3). So, we have 3 x 3 = 9 oxygen atoms on the left side. To balance this, we need 9 oxygen atoms on the right side as well. Since each molecule of aluminum oxide (Al2O3) contains 3 oxygen atoms, we can achieve this by placing a coefficient of 3 in front of Al2O3:

Al2(CO3)3 -> 3Al2O3 + 3CO2

4. Finally, let's check if the aluminum atoms are balanced.

On the left side, there are 2 aluminum atoms. On the right side, we have 3 molecules of aluminum oxide, and each molecule contains 2 aluminum atoms. Therefore, we have a total of 3 x 2 = 6 aluminum atoms on the right side. To balance the aluminum atoms, we place a coefficient of 3 in front of Al2(CO3)3:

3Al2(CO3)3 -> 3Al2O3 + 3CO2

Now the equation is balanced, and the product of the decomposition of solid aluminum carbonate is 3 moles of solid aluminum oxide and 3 moles of carbon dioxide gas for every 3 moles of solid aluminum carbonate.