college algebra
posted by Anonymous .
√3x+7=3x+5
How do I solve when the answer is 1?

Squaring both sides
3 x + 7 = ( 3 x + 5 ) ^ 2
3 x + 7 = 9 x ^ 2 + 2 * 3 x * 5 + 5 ^ 2
3 x + 7 = 9 x ^ 2 + 30 x + 25
0 = 9 x ^ 2 + 30 x + 25  3 x  7
9 x ^ 2 + 27 x + 18 = 0 Divide both sides by 9
x ^ 2 + 3 x + 2 = 0
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x ^ 2 + 3 x + 2 = 0
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