Volume of reaction flask is 2ml.
There are 273 nanomoles of molecular oxygen (O2)/ml of reaction volume at 25*C. What is the amount of atomic oxygen (nanomoles) in the reaction flask?
each O2 has 2 atomic O. The volume/temperature data are just noise.
I interpret the problem a little differently than Steve.
273 nmols/mL x 2 mL = total nmols O2.
Then nmoles atomic O2 is twice that so
4*273 = ? nanomols atomic O2.
(or we could say that technically there are NO O atoms since all are tied up as molecules). However, I think the spirit of the question is 4*273 = ?
To find the amount of atomic oxygen in the reaction flask, we need to calculate the number of nanomoles of atomic oxygen per milliliter (ml) and then multiply it by the volume of the reaction flask.
Given:
Volume of reaction flask = 2 ml
Molecular oxygen (O2) = 273 nanomoles/ml
Since 1 molecule of O2 contains 2 atoms of oxygen, we need to divide the number of nanomoles of O2 by 2 to find the number of nanomoles of atomic oxygen.
273 nanomoles O2 / 2 = 136.5 nanomoles atomic oxygen/ml
Now we can calculate the amount of atomic oxygen in the reaction flask by multiplying the number of nanomoles of atomic oxygen per ml by the volume of the reaction flask.
136.5 nanomoles atomic oxygen/ml * 2 ml = 273 nanomoles atomic oxygen
Therefore, the amount of atomic oxygen in the reaction flask is 273 nanomoles.