calculus 1
posted by visoth .
differentiate x(x3)^2
do I product and chain rule?

f= uv
f'=uv'+vu'
f'= 1*(x3)^2+ 2x(x3)*1 
shouldn't it be 1 * (x3)^2 + 2x(x3)^1 ? instead of 2x(x3) * 1 at the end?

oh wait nvm i see what i did wrong

x(x3)^2
=x(x3)(x3)
=x(x^23x3x+9)
=x^36x^2+9x
=3x^212x+9