# Collage Physics

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An elevator with a man inside, of gross mass 500KG, starts moving upwards with a costant acceleration and acquires a velocity os 2m/s after travelling a distance os 3m.Find the pull in the cables during the accelerated motion.

If the elevator, before stopping, moves with a constant deceleration from a constant velocity of 2m/s and comes to rest in 2 second, calculate the force exerted by the man of 75kg mass on the floor on the elevator.

• Collage Physics -

The pull of cable is 5.24x10^3N
The force exerted by the man =75N
Is it correct?

• Collage Physics -

first, find the acceleration.
Vf^2=Vi^2+2ad

4=0+2a*3

a=2/3 m/s^2

then

force= m(g+a)=500(9.8+2/3) =

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