# college physics

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A 30.3-kg child starting from rest slides down a water slide with a vertical height of 10.5 m. (Neglect friction.)
(a) What is the child's speed halfway down the slide's vertical distance?

• college physics -

V^2 = Vo^2 + 2g*d
V^2 = 0 + 19.8*(10.5-5.25)
V^2 = 1102.9
V = 10.1 m/s.

• college physics -

Correction: V^2 = 102.9.

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