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A 3.6 kg ball strikes a wall with a velocity of 9.3 m/s. The ball bounces off with a velocity of 7.9 m/s in the opposite direction. If the ball is in contact with the wall for 0.4 seconds, what is the constant force exerted on the ball by the wall?

  • Physics -

    = mass(Vf-Vi)
    = mass(7.9+9.3)
    solve now for force.

    Notice the sign change in velocity, that is what OPPOSITE direction is, a sign change.

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