Questions LLC
Login
or
Sign Up
Ask a New Question
Math
Calculus
F(x) log_3 (1-5x)
F'(x)=
1 answer
is that log base 3?
g(x)=loga(x)
g'(x)= 1/(x * ln(a))
You can
ask a new question
or
answer this question
.
Similar Questions
Rewrite the expression log_3(z) + log_3(2) + log_3(4) as a single logarithm. (1 point)
1)log_3 (8z) 2)log_3 (24z) 3) log_3 (z+6)
Top answer:
2) log_3 (24z)
Read more.
Solve:
2log_3(x) - log_3(x-2) = 2 My Work: log_3(x^2) - log_3(x-2) = log_3(3^2) log_3 [(x^2) / (x-2)] = log_3(27) (x^2) / (x-2) =
Top answer:
log_3(x^2/(x-2)) = 2 nothing changed on the right x^2/(x-2) = 3^2 = 9 x^2 = 9x - 18 x^2 -9x + 18 = 0
Read more.
Rewrite the expression log_3(z) + log_3(2) + log_3(4) as a single logarithm. (1 point)
Rewrite the expression log_3(z) + log_3(4) + log_3(4) as a single logarithm. (1 point)
Top answer:
log_3(z) + log_3(4) + log_3(4) = log_3(z) + 2log_3(4) = log_3(z*4^2) = log_3(16z)
Read more.
log_3(2x - 1) = 2, Find x.
Here's what I've done: log_3(2x) * log_3(1) = 2 log2x/log3 * log1/log3 = 2 trial and error... log2
Top answer:
3^log_3(2x - 1) = 3^2 but 3^log3 a = a for any a so 2 x - 1 = 3^2 = 9 2 x = 10 x = 5
Read more.
Given that x=log_3 5 and y=log_3 2, rewrite log_3 60 in terms of x and y.
Top answer:
60 = 3 (5 * 2 * 2) log_3 60 = 1 + x + 2y
Read more.
Which of the following logarithmic expressions is undefined?
(1 point) 1) log_0.25 (64) 2) log_3 (-9) 3) log_2.5 (6.25)
Top answer:
2) log_3 (-9)
Read more.
Write the expression as a single logarithm.
log_3 40-log_3 10 I'm completely confused with logarithmic equations!! Can someone
Top answer:
since loga - logb = log(a/b), we have log_3 40-log_3 10 = log_3(40/10) = log_3(4) logs are just
Read more.
Select the correct answer.
What is the solution to this equation? log_3 (4x) - 2 log_3 x = 2 A. 4/9 B. 36 C. 9/4 D. 1/36
Top answer:
C. 9/4
Read more.
Solve the equation:log_3(x²+x)-log_3(x²-x)=1
Top answer:
Using the logarithmic identity log_b(a) - log_b(c) = log_b(a/c), we can rewrite the equation as:
Read more.
Related Questions
find the zero(es) of the function f(x)=log_3(x-1)+log_3(2x+3)
a. x=2 and x=-1 b. x=1 and x=-2/3 c. x=-1+ sqr 33/4 d. x=-1 +- sqr
log_5[log_4(log_3(x))] = 1
log_5 = log with the base of 5 log_4 = log with the base of 4 log_3 = log with the base of 3 Answer:
I need to justify how a base in a logarithmic function graph is a base. Here are the choices:
The graph of f(x)= log_3 x+c must
What is the value of log_3 (9^x)
F(x)= log_3 (1-5x)
F'(x)=
log_3 (3)^(2x)
the inverse of f(x) = log_3(x') ?
Find f’(x) if f(x) = 3^g(x) where g(x) = LOG_3(x^2 - √x + 4/x + 10*LOG_e(x))
Solve for x and y if log_2(x+y)=log_3(3x+4y)=3
Expand the logarithm log_3(h/9)(1 point)