A solution is prepared by dissolving 0.12 mol of acetic acid and 0.12 mol of ammonium chloride in enough water to make 1.0 L of solution. Find the concentration of ammonia in the solution.
I posted a response to this yesterday. Did that solution not take care of it?
To find the concentration of ammonia in the solution, we need to calculate the number of moles of ammonia present.
First, we need to find the number of moles of ammonium chloride (NH4Cl) in the solution. Since the molar ratio between NH4Cl and NH3 is 1:1, the number of moles of ammonia is the same as the number of moles of ammonium chloride.
Given:
- Moles of acetic acid (CH3COOH) = 0.12 mol
- Moles of ammonium chloride (NH4Cl) = 0.12 mol
- Volume of solution = 1.0 L
Since 0.12 mol of ammonium chloride is dissolved in 1.0 L of solution, the concentration of ammonium chloride is:
Concentration of NH4Cl = Moles of NH4Cl / Volume of Solution
Concentration of NH4Cl = 0.12 mol / 1.0 L = 0.12 M
As the molar ratio between NH4Cl and NH3 is 1:1, the concentration of ammonia (NH3) in the solution is also 0.12 M.