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The ball is throw in to the air . If its height in feet is given by - 16t^2 + 64t, at what time t will the ball reach a height of 64 feet?

  • physics -

    just solve

    - 16t^2 + 64t = 64
    Let's get rid of that pesky factor of -16, leaving

    t^2 - 4t + 4 = 0
    (t-2)^2 = 0
    t = 2

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