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A ball of mass 0.750 kg is attached to the end of a 1.20m long cord that can withstand a maximum tension of 50.0 N. If swung in a vertical circle, what is the maximum velocity the ball can achieve before the string breaks?

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    Since the circle is vertical, maximum tension is experienced when the ball is at the bottom of the loop. Tension must support both weight and centripetal force.

    Require that
    M*V^2/R + M*g = (maximum tension) Tmax
    = 50.0 N

    Then solve for V.

    M*V^2/R = 50 - 7.35 = 42.65 N
    V = sqrt(42.65*1.2/0.75)= 8.26 m/s

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