Suppose that the magnetic field in the figure below has a magnitude of 1.1 T, the rod has a length of 0.83 m, and the hand keeps the rod moving to the right at a constant speed of 3.8 m/s. If the current in the circuit is 0.045 A, what is the average power being delivered to the circuit by the hand?
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To find the average power being delivered to the circuit by the hand, you can use the equation:
Power = Force × Velocity
First, we need to determine the force acting on the rod. The force can be calculated using the equation:
Force = Magnetic field × Current × Length
Using the given values:
Magnetic field (B) = 1.1 T
Current (I) = 0.045 A
Length (L) = 0.83 m
Substituting these values into the equation, we get:
Force = (1.1 T) × (0.045 A) × (0.83 m)
Next, we need to calculate the velocity of the rod, which is given as 3.8 m/s.
Now, using the obtained force and the given velocity, we can calculate the average power using the equation mentioned earlier:
Average Power = Force × Velocity
Substituting the values:
Average Power = (Force) × (Velocity)
Finally, plug in the calculated force and the given velocity to find the average power being delivered to the circuit by the hand.