calculus
posted by akash .
Find dy/dx.
y^3 = 8x^3 + 4x

3y^2 dy=24x^2 dx + 4dx
dy/dx=(8x^2+1)/(y^2) check that 
bob probably meant to type
dy/dx = (8x^2 + 4/3)/(y^2)
posted by akash .
Find dy/dx.
y^3 = 8x^3 + 4x
3y^2 dy=24x^2 dx + 4dx
dy/dx=(8x^2+1)/(y^2) check that
bob probably meant to type
dy/dx = (8x^2 + 4/3)/(y^2)