Near San Francisco, where the vertically downward component of the earth's magnetic field is 4.7 10-5 T, a car is traveling forward at 26 m/s. The width of the car is 1.7 m.
(a) Find the emf induced between the two sides of the car.
V
(b) Which side of the car is positive—the driver's side or the passenger's side?
driver's side
passenger's side
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To find the electromotive force (emf) induced between the two sides of the car, we need to use the equation:
emf = B * v * d,
where B is the magnetic field strength, v is the velocity of the car, and d is the width of the car.
In this case,
B = 4.7 * 10^-5 T (given),
v = 26 m/s (given),
d = 1.7 m (given).
(a) Plugging in the given values into the formula, we find:
emf = (4.7 * 10^-5 T) * (26 m/s) * (1.7 m)
= 2.6386 * 10^-5 V
≈ 2.64 * 10^-5 V.
Therefore, the emf induced between the two sides of the car is approximately 2.64 * 10^-5 volts.
(b) To determine which side of the car is positive, we can use the right-hand rule. If we point our right thumb in the direction of the velocity vector (forward in this case), and place our fingers perpendicular to the magnetic field pointing downwards, then the positive side of the car will be the side that our fingers curl towards.
In this scenario, the car is traveling forward, so the driver's side of the car (left side) is the positive side.
Therefore, the driver's side of the car is positive, and the passenger's side is negative.