two blocks a and b are connected by a cord passes over a frictionless pulley. the mass of a is 1.2 kg and the magnitude of acceleration is 3.6
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To solve this problem, we can use Newton's second law of motion and analyze the forces acting on each block.
Let's label the mass of block A as mA = 1.2 kg and the magnitude of acceleration as a = 3.6 m/s^2.
For block A, the forces acting on it are the tension in the cord (T) and its weight (mg). Since the block moves vertically, we can write the equation of motion for block A as:
m*A*a = T - m*A*g
Here, m*A is the mass of block A and g is the acceleration due to gravity (9.8 m/s^2).
Now, let's consider block B. Since the cord is passing over a frictionless pulley, the tension (T) in the cord will be the same on both sides. Therefore, we have:
T = m*B*a
Here, m*B is the mass of block B.
To find the value of m*B, we need more information or equations. Without any additional information, we cannot determine the mass of block B or any other parameters of the system. Please provide more information, such as the value of block A's weight or the relationship between the two masses, so that we can solve the problem.