Solve for B: square root b^4/25 = 4.
A.) 2
B.) +/- 5 square root 2
C.) 3
D.) +/- 2 square root 5
I don't know how to do these so please show your work.
Thank you.
√(b^4/25) = 4
b^2/5 = 4
b^2 = 20
b = ±√20, but since 20=4*5,
b = ±2√5
So which is it?
woops Steve is right, I did not see the sqrt before the equation.
So we get 16 = b^4/25
Simplifying we get 25*16 = 400
b^4 = 400
b^2 = 20
so, b^2 = sqrt 2^2 * 5
so, b = +/- 2 sqrt 5
answer is D
Sorry for inconvenience
*Sorry for any inconveniences caused to you.
Thank you for all your help...I appreciate it.
To solve for B in the equation √(b^4/25) = 4, you can follow these steps:
Step 1: Square both sides of the equation to eliminate the square root:
(√(b^4/25))^2 = 4^2
This simplifies to:
b^4/25 = 16
Step 2: Multiply both sides of the equation by 25 to isolate the b^4 term:
b^4 = 16 * 25
b^4 = 400
Step 3: Take the fourth root of both sides of the equation to solve for b:
∛(b^4) = ∛400
This simplifies to:
b = ± ∛400
Step 4: Simplify the cube root of 400:
b = ± ∛(8 * 50)
b = ± (2 * ∛50)
Finally, we can simplify further:
b = ± 2 * √(5) * √(2)
So, the answer is D) ±2√5
we cross multiply or multiply both sides by 25 to get b^4 = 100
sqrt of both sides gives us sqrt b^4 = sqrt 100 =
sqrt b^2 * b^2 = 10
b^2 = 10
b = +/- sqrt 10
which is roughly equal to +/- 3.1623...