Algebra: Please help

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Solve for B: square root b^4/25 = 4.

A.) 2
B.) +/- 5 square root 2
C.) 3
D.) +/- 2 square root 5

I don't know how to do these so please show your work.

Thank you.

  • Algebra: Please help -

    we cross multiply or multiply both sides by 25 to get b^4 = 100

    sqrt of both sides gives us sqrt b^4 = sqrt 100 =
    sqrt b^2 * b^2 = 10

    b^2 = 10

    b = +/- sqrt 10

    which is roughly equal to +/- 3.1623...

  • Algebra: Please help -

    √(b^4/25) = 4
    b^2/5 = 4
    b^2 = 20
    b = ±√20, but since 20=4*5,
    b = ±2√5

  • Algebra: Please help -

    So which is it?

  • Algebra: Please help -

    woops Steve is right, I did not see the sqrt before the equation.

    So we get 16 = b^4/25

    Simplifying we get 25*16 = 400

    b^4 = 400

    b^2 = 20

    so, b^2 = sqrt 2^2 * 5

    so, b = +/- 2 sqrt 5

    answer is D

    Sorry for inconvenience

  • Algebra: Please help -

    *Sorry for any inconveniences caused to you.

  • Algebra: Please help -

    Thank you for all your help...I appreciate it.

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