algebra

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x3-48x-128=0
x3-12x+16=(x-2)2(x+4)

Is this correct answer?
Thanks for your help.

  • algebra -

    x ^ 3 - 48 x - 128 = ( x - 8 ) ( x + 4 ) ^ 2

    Solutions : x = - 4 and x = 8


    x ^ 3 - 12 x + 16 = ( x - 2 ) ^ 2 ( x + 4 )

    Solutions : x = - 4 and x = 2

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