x3-48x-128=0
x3-12x+16=(x-2)2(x+4)
Is this correct answer?
Thanks for your help.
x ^ 3 - 48 x - 128 = ( x - 8 ) ( x + 4 ) ^ 2
Solutions : x = - 4 and x = 8
x ^ 3 - 12 x + 16 = ( x - 2 ) ^ 2 ( x + 4 )
Solutions : x = - 4 and x = 2
x3-12x+16=(x-2)2(x+4)
Is this correct answer?
Thanks for your help.
Solutions : x = - 4 and x = 8
x ^ 3 - 12 x + 16 = ( x - 2 ) ^ 2 ( x + 4 )
Solutions : x = - 4 and x = 2