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find all solutions to 4tanθ + √3 = tanθ

  • math -

    4tanθ + √3 = tanθ
    3tanØ = -√3
    tanØ = -√3/3
    Ø must be in II or IV
    Ø = 150° or 330°
    Ø = 5π/6 or 11π/6

    period of tanØ = 90°
    general solutions:
    =(150+90k)° or 330° +90k°

    do the same with the radian answer by adding πk/2 to each of the answers

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