# math

posted by .

find all solutions to 4tanθ + √3 = tanθ

• math -

4tanθ + √3 = tanθ
3tanØ = -√3
tanØ = -√3/3
Ø must be in II or IV
Ø = 150° or 330°
or
Ø = 5π/6 or 11π/6

period of tanØ = 90°
general solutions:
=(150+90k)° or 330° +90k°

## Similar Questions

1. ### mathematics

given tanθ= -2√10/3 and π/2<θ< π find: a.sin2θ b.tan θ/2 could some1 help me with these 2 they're the only ones i couldn't get
2. ### Pre-Calculus

If θ represents an angle such that sin2θ = tanθ - cos2θ, then sin θ - cosθ = A. -√2 B. 0 C. 1 D. 2√2 What equation can I use to solve this problem?
3. ### math trigono

1. If tanθ = –√3 , what is the value of cot ?
4. ### Math (Trigonometry)

θ is an acute angle such that tan(θ) = 12. What is the value of 5√5⋅(sinθ+cosθ)?
5. ### Math (Trigonometry)

θ is an acute angle such that tan(θ)=1/4. What is the value of 17√17*(sinθ+cosθ)?
6. ### Trig

Given that tan θ = - (√3/8) and θ is in QII, find the exact value of a. r = b. csc θ c. cos θ d. cot θ
7. ### Trigonometry

Could someone please help me with the following q's I'm having some trouble: 1.) cot θ (theta) = 0.791, find sec θ and tan θ 2.) tan θ = 9/40, what is the value sin^2θ + cos^2θ
8. ### Precalc/Trig

Sorry there are quite a few problems, but I just need to know if these are correct (and if they aren't, where I went wrong): 1. Solve these equations. tanθ = -√3 θ = 2π/3 + kπ θ = 5π/3 + kπ …
9. ### math

Given that sinθ = 2/3 and is an acute angle. Find: Tanθ giving your answer in surd form θ = tan^(-1)⁡〖(2/√5)= 41.81°〗 Sec^22 θ θ= cos^(-1)⁡〖(3/√5〗)=