Calculate the pH of a buffer solution containing 1.0 M ammonia (NH3 ; Kb = 1.8 x 10-5) and 1.0 M ammonium chloride (NH4Cl).

Use the Henderson – Hasselbalch equation.

4.77

To calculate the pH of a buffer solution, we can use the Henderson-Hasselbalch equation, which is given by:

pH = pKa + log ([A-]/[HA])

where:
pH is the pH of the buffer solution,
pKa is the negative logarithm of the acid dissociation constant of the weak acid in the buffer solution,
[A-] is the concentration of the conjugate base,
[HA] is the concentration of the weak acid.

In this case, ammonia (NH3) acts as the weak base, and ammonium chloride (NH4Cl) provides the conjugate acid (NH4+).

The pKa can be calculated using the equation:

pKw = pKa + pKb

where pKw is the negative logarithm of the water dissociation constant (pKw = 14), and pKb is the negative logarithm of the base dissociation constant.

Given that the base dissociation constant (Kb) for ammonia (NH3) is 1.8 x 10^-5, we can calculate pKb as follows:

pKb = -log(Kb) = -log(1.8 x 10^-5) = 4.74

Substituting the pKw value and pKb value into the pKa equation, we can solve for pKa:

14 = pKa + 4.74

pKa = 14 - 4.74 = 9.26

Now, we can use the Henderson-Hasselbalch equation to calculate the pH of the buffer solution:

pH = pKa + log ([A-]/[HA])

Since the concentration of ammonia (NH3) and ammonium chloride (NH4Cl) in the buffer solution is both 1.0 M, we have:

pH = 9.26 + log (1.0/1.0) = 9.26 + log(1) = 9.26

Therefore, the pH of the buffer solution is 9.26.

To calculate the pH of a buffer solution, you need to consider the equilibrium reactions that happen between the weak acid (NH4+) and its conjugate base (NH3) in the buffer system.

In this case, ammonia acts as a weak base (NH3) and ammonium chloride (NH4Cl) acts as its conjugate acid (NH4+).

The equilibrium reactions involved are as follows:

NH3 + H2O ⇌ NH4+ + OH-

NH4+ + H2O ⇌ NH3 + H3O+

The dissociation constant of ammonia, Kb, is given as 1.8 x 10^-5, which represents the equilibrium constant for the reaction NH3 + H2O ⇌ NH4+ + OH-.

The first step is to determine the concentration of the hydroxide ion (OH-) in the solution. Since we are given that the concentration of ammonia (NH3) is 1.0 M, the concentration of hydroxide ions can be calculated from Kb using the following equation:

Kb = [NH4+][OH-] / [NH3]

Using the given value of Kb and the concentration of ammonia (NH3) as 1.0 M, we can rearrange the equation to solve for [OH-], which is the concentration we need:

[OH-] = Kb * [NH3] / [NH4+]

Now, let's calculate the concentration of NH4+ in the solution. Since the concentration of ammonium chloride (NH4Cl) is also given as 1.0 M, the concentration of NH4+ is also 1.0 M.

Substituting the values into the equation, we have:

[OH-] = (1.8 x 10^-5) * (1.0) / (1.0) = 1.8 x 10^-5 M

Since the buffer solution contains equal concentrations of NH3 and NH4+, we know that [NH3] = [NH4+] = 1.0 M.

To determine the pH of the buffer solution, we can use the fact that pH is the negative logarithm of the concentration of hydronium ions (H3O+). In this case, we need to calculate the concentration of H3O+.

Since the reaction NH4+ + H2O ⇌ NH3 + H3O+ is in equilibrium, the concentration of H3O+ is the same as the concentration of NH4+, which is 1.0 M.

Therefore, the pH of the buffer solution can be calculated as follows:

pH = -log[H3O+] = -log(1.0) = 0

So, the pH of the buffer solution containing 1.0 M ammonia (NH3) and 1.0 M ammonium chloride (NH4Cl) is 0.