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Prove:

3/(log_2 (a)) - 2/(log_4 (a)) = 1/(log_(1/2)(a))

  • math -

    3/(log_2 (a)) - 2/(log_4 (a)) = 1/(log_(1/2)(a))

    since 4 = 2^2, log_4(a) = 1/2 log_2(a)
    since 1/2 = 2^-1, log_(1/2)(a) = -log_2(a)

    so, if we let x = log_2(a), we have

    3/x - 2/(x/2) = 1/(-x)
    3/x - 4/x = -1/x
    (4-3)/x = -1/x
    1/x = -1/x
    ???

    Is there a typo somewhere ?

  • math -

    i.imgur[dot]com/hE0sWBt[dot]gif

  • math -

    Make sure its just like that, it has to be solvable o.o

  • math -

    er "prove-able"

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