The current in a 5.00mH inductor drops from 2.50A to zero in 5.ooms. What is the average emf induced in he inductor?

To find the average electromotive force (emf) induced in the inductor, we can use Faraday's law of electromagnetic induction. Faraday's law states that the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit.

The formula for Faraday's law is:

emf = -dΦ/dt

where emf is the electromotive force, dΦ is the change in magnetic flux, and dt is the change in time.

In this case, we can assume that the inductor is connected to a circuit where the current drops from 2.50A to zero in 5.00 ms. We can calculate the change in magnetic flux using the formula:

ΔΦ = L * ΔI

where ΔΦ is the change in magnetic flux, L is the inductance of the inductor (5.00 mH = 5.00 × 10^-3 H), and ΔI is the change in current (2.50 A - 0 A = 2.50 A).

Substituting the given values into the formula:

ΔΦ = (5.00 × 10^-3 H) * (2.50 A) = 1.25 × 10^-2 Wb

Now, we can calculate the average emf by dividing the change in magnetic flux by the change in time:

Average emf = ΔΦ / Δt

where Δt is the change in time (5.00 ms = 5.00 × 10^-3 s).

Substituting the given values into the formula:

Average emf = (1.25 × 10^-2 Wb) / (5.00 × 10^-3 s) = 2.50 V

Therefore, the average emf induced in the inductor is 2.50 V.