Solution x has a pH of 4.35. Solution y has 10- times high [OH-] compared to solution x. Solution z has a pH 4.0 units higher than that of solution x.
calculate the ration of [H3O+] between solutions x&y and between x&z.
What is the pH of solutions y and z?
classify each solution as acidic, basic,or neutral.
I don't know what 10-times high [OH-] means.
Oh, sorry. I meant to say that solution y has a 10 times higher OH- concentration compared to solution x. I hope it makes sense now. :-)
Mary
pH x = 4.35; therefore, pOH = 9.65
y has 10x higher OH; therefore, pOH must be 8.65 which makes pH = 14-8.35 = 5.35
z is 4.35 + 4.0 = 8.35
You can change these to H^+ and calculate the ratio and classify as acid, base, neutral.
Thanak you so much for your help, DrBob222
To calculate the ratio of [H3O+] (hydronium ion concentration) between solutions x and y, we can use the equation:
pH = -log[H3O+]
Since we know the pH of solution x (4.35), we can find [H3O+] by rearranging the equation:
[H3O+] = 10^-pH
Substituting the value of pH for solution x:
[H3O+]x = 10^-4.35
Similarly, we know that solution y has 10 times higher [OH-] (hydroxide ion concentration) than solution x. Remember that in an aqueous solution, [H3O+] and [OH-] are related by the equation:
[H3O+][OH-] = 10^-14
Since we have the value of [OH-]y in terms of 10 times compared to solution x, we can substitute it in the equation:
[H3O+]x * [OH-]y = 10^-14
To find the ratio of [H3O+] between solutions x and y, we can rearrange the equation:
[H3O+]y = 10^-14 / [H3O+]x = [OH-]y
Now, to find the pH of solution y, we can use the equation:
pOH = -log[OH-]
Since we have the ratio [OH-]y compared to solution x, we can calculate pOH for solution y and then convert it to pH:
pOH = -log[OH-]y
Finally, to calculate the pH of solution y, we subtract pOH from 14:
pH of solution y = 14 - pOH
For solution z, we are given that its pH is 4.0 units higher than that of solution x. Therefore, we can calculate its pH by adding 4.0 to the pH of solution x:
pH of solution z = pH of solution x + 4.0
Now, let's classify each solution as acidic, basic, or neutral based on their pH values:
- If the pH is less than 7, the solution is acidic.
- If the pH is greater than 7, the solution is basic.
- If the pH is equal to 7, the solution is neutral.
By examining the pH values we calculated for solutions x, y, and z, we can determine their classifications.