peter, a 100 kg baketball player, lands on his feet after completeing a slam dunk and then immediately jumps up again to celebrate his basket. when his feet frist touch the floor after the dunk, his velocity is 5 m/s downward, and when his feet leave the floor .50 s later, as he jumps back up, his velocity is 4 m/s upward. what is the impulse exerted on peter during this .50s> what is the average net force exterted on peter during this .50s?
What is it?
900kg
1800n
To find the impulse exerted on Peter during the 0.50 seconds, we can use the principle of conservation of momentum.
Impulse is defined as the change in momentum. Momentum is given by the equation:
Momentum = mass x velocity
Given that Peter's mass is 100 kg, his initial velocity after the dunk is 5 m/s downward, and his final velocity as he jumps back up is 4 m/s upward, we can calculate the impulse as follows:
Change in momentum = final momentum - initial momentum
Initial momentum = mass x initial velocity
Initial momentum = 100 kg x (-5 m/s) = -500 kg.m/s
Final momentum = mass x final velocity
Final momentum = 100 kg x 4 m/s = 400 kg.m/s
Change in momentum = 400 kg.m/s - (-500 kg.m/s) = 900 kg.m/s
Therefore, the impulse exerted on Peter during the 0.50 seconds is 900 kg.m/s.
To find the average net force exerted on Peter during this time, we can use the equation:
Impulse = average net force x time
Rearranging the equation, we get:
Average net force = Impulse / time
Substituting the values, we find:
Average net force = 900 kg.m/s / 0.50 s = 1800 N
Therefore, the average net force exerted on Peter during this time is 1800 Newtons.
To find the impulse exerted on Peter, we can use the impulse-momentum principle, which states that the impulse exerted on an object is equal to the change in momentum of the object.
The impulse can be calculated using the formula:
Impulse = Change in momentum
The change in momentum can be found by subtracting the initial momentum from the final momentum.
Momentum (p) is given by the formula:
Momentum = mass × velocity
Initial momentum = mass × initial velocity
Final momentum = mass × final velocity
Let's calculate the impulse on Peter:
1. Calculate the initial momentum:
Initial momentum = mass × initial velocity
Initial momentum = 100 kg × (-5 m/s) (since the velocity is downward)
Initial momentum = -500 kg·m/s
2. Calculate the final momentum:
Final momentum = mass × final velocity
Final momentum = 100 kg × 4 m/s (since the velocity is upward)
Final momentum = 400 kg·m/s
3. Calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
Change in momentum = 400 kg·m/s - (-500 kg·m/s)
Change in momentum = 900 kg·m/s
Therefore, the impulse exerted on Peter during the 0.50 seconds is 900 kg·m/s.
To find the average net force exerted on Peter during this 0.50 seconds, we can use the relationship between impulse and force:
Impulse = Average net force × time
Let's rearrange the formula to solve for the average net force:
Average net force = Impulse / time
4. Calculate the average net force:
Average net force = Impulse / time
Average net force = 900 kg·m/s / 0.50 s
Average net force = 1800 N
Therefore, the average net force exerted on Peter during the 0.50 seconds is 1800 Newtons.